Home Products Blog/News FAQ About Us Contact

Crane Harmonic Distortion: What Five Drives on One Busbar Do to a Double Girder, 5 to 100 Ton

A 20 tonne double girder is five drives and 24.1 kW on one busbar, not one crane's worth of load. Even with a 5 percent reactor on every drive the busbar lands near 18 percent total demand distortion against an 8 percent limit. Here is what actually adds up, and which fix belongs to which crane.

Written by Chen Wei, Senior Design Engineer at SIEC Cranes. Oct 30, 2026.

A 20 tonne double girder is not one crane's worth of electrical load. A typical catalogue entry lists a 16 kW main hoist, a 2.6 kW auxiliary hoist, two 0.55 kW trolley motors and four 1.1 kW long-travel motors. That is 24.1 kW spread across five drives hanging on one busbar. When they run together the harmonic currents add before they ever reach your transformer, and no single-drive calculation predicts what your meter will read.

I have been on three jobs this year where a new double girder tripped a plant that had run single girder cranes for a decade. All three were argued about as if the crane were defective. Two of them were busbar problems, one was a panel cooling problem, and none of them were the crane.

The reason double girders behave differently comes down to two things the single girder article on this site did not have to deal with. There are more drives, and above 16 tonnes there are two hoists. Two hoists means two rectifiers, two sets of brake control and two chances for a contactor to drop out at the wrong moment. The arithmetic that follows is about what those drives do to each other.

Everything below is either a published figure with the source named, a standard clause, or a number we computed. Computed numbers are labelled as planning figures. Nobody has published a survey of harmonic distortion on a 20 tonne double girder in a Vietnamese steel mill, and I am not going to pretend otherwise.

How many drives does a 5 to 100 tonne double girder actually put on one busbar?

More than buyers count. A single girder at 10 tonnes has one hoist, one trolley set and two long-travel motors. A double girder at the same tonnage has four long-travel motors because each end carriage carries two, and from 16 tonnes upward it also has a second hoist for the light lifts. The published motor breakdown below is from a standard double girder catalogue covering 5 to 40 tonnes, with the totals as printed.

Capacity Hoisting motor Trolley motors Long travel motors Crane power Drives on the bar Current at 400 V
5 t 6.1 / 1 kW 2 x 0.31 kW 2 x 0.55 kW 8.82 kW 3 16.6 A
10 t 9.5 / 1.5 kW 2 x 0.44 kW 2 x 1.1 kW 14.08 kW 4 26.6 A
20 t 16 / 2.6 kW 2 x 0.55 kW 4 x 1.1 kW 24.1 kW 5 to 7 45.5 A
32 t 20 / 5.0 kW 2 x 1.1 kW 4 x 1.5 kW 33.2 kW 5 to 7 62.6 A
40 t 38 kW 2 x 1.5 kW 4 x 2.2 kW 47.0 kW 5 to 7 88.7 A
50 t (European light) 4 / 0.67 m/min, 2 speed 20 / 5 m/min 40 / 10 m/min, pole change 44.4 kW 4 83.8 A

Currents are our calculation at 400 V, power factor 0.85 and motor efficiency 0.90, using the catalogue kilowatts. The drive count is the number of separately switched motors, which is what matters for harmonics: each motor with its own inverter injects its own current distortion at its own point on the busbar. Our own double girder crane listings publish the same breakdown per capacity, and it is the first thing worth comparing between two quotations.

The 50 tonne line is worth pausing on. It is a real published machine, 13.5 m span, 6 m lift, 8,950 kg bridge and 12,810 kg total weight, 134.5 kN maximum static wheel load, classification U4/Q2 to EN 13001-1, and 44.4 kW of electrical equipment. It has no inverter anywhere. Hoisting is 4/0.67 m/min on a two-speed pole-change motor and long travel is 40/10 m/min the same way. Keep that in mind, because it changes what you should worry about.

What changes when the second hoist arrives?

Two hoists on one bridge is not a redundancy feature. It is a productivity feature: the auxiliary hook moves at 2 to 5 times the speed of the main hook and handles everything under about a quarter of rated capacity. On a machine that spends most of its day lifting 2 tonnes, the main hoist is dead weight.

The published configuration list of a heavy double girder range makes the pattern obvious. From 16 tonnes upward every capacity is written as a pair.

Listed capacity Main / auxiliary Auxiliary share of main
5 tsingle hooknone
10 tsingle hooknone
16 t16 / 3.2 t20 percent
20 t20 / 5 t25 percent
32 t32 / 5 t16 percent
50 t50 / 10 t20 percent
75 t75 / 20 t27 percent
100 t100 / 20 t20 percent
125 t and above125 / 32 t and upward25 to 30 percent

This is where the electrical story departs from the single girder. The auxiliary hoist is a second rectifier, a second brake control circuit and a second motor cable, and it is deliberately sized small. Small drives are the ones with the worst current distortion relative to their own load, because the DC bus capacitance and the reactor, if there is one, are chosen against a small frame size rather than against the harmonics. The same logic applies to the hoist and accessory side of the order: the small unit is not the simple one.

Two 6-pulse rectifiers on one busbar do not average out. A published laboratory demonstration on two drives from a common AC bus measured 10.9 A of fifth harmonic from the first drive and roughly twice that with the second drive running. One plus one equals two, as the Eaton application note puts it. The waveforms are similar, the phase angles are similar, and similar angles add.

Do the harmonics of five drives add up, or average out?

Between the two extremes, and the gap is the whole discussion. The convenient assumption is arithmetic addition: five drives, five times the harmonic current. The optimistic assumption is root sum square: five drives, 2.24 times the harmonic current. Reality sits between them and depends on how similar the drives are and whether their rectifiers are phase shifted.

The industry quantifies this with a summation exponent, often written alpha. An exponent of 1 is arithmetic addition with no cancellation. An exponent of 2 is the root sum of squares, which is what you get when phase angles are randomly distributed. A 2013 IEEE paper by Cuk, Cobben, Ribeiro and Kling measured parallel induction motor drives at two sites for a week with one-second resolution, covering both 6-pulse and 12-pulse front ends, and derived coefficients for simplified summation precisely because neither extreme is right.

What matters practically is total demand distortion at the busbar, not total harmonic distortion of one drive. Those are different numbers and buyers mix them up constantly. Here is what the two addition rules produce for a group of identical drives.

Drives on the busbar TDD if arithmetic, no reactor (THDi 100 percent) TDD if root sum square, no reactor TDD if arithmetic, 5 percent reactor (THDi 40 percent) TDD if root sum square, 5 percent reactor
1100 percent100 percent40 percent40 percent
2100 percent71 percent40 percent28 percent
3100 percent58 percent40 percent23 percent
5100 percent45 percent40 percent18 percent
7100 percent38 percent40 percent15 percent
IEEE 519-2022 limit, Isc/IL 20 to 508 percent8 percent8 percent8 percent

Our own calculation, using the per-drive THDi ranges published by ABB for HVAC drives and the standard addition rules. The table says something uncomfortable. Even if every drive has a 5 percent reactor and the phase angles happen to distribute perfectly, a five-drive double girder lands at 18 percent TDD against an 8 percent limit. Adding reactors helps the individual drive enormously and still leaves the busbar out of compliance.

That is not a reason to skip the reactor. It is a reason to stop believing the reactor is the whole answer. On a single drive the same table shows 40 percent falling to 18 percent, which is why the reactor is worth its two hundred dollars. On a five-drive machine the same reactor buys you from 100 to 18, which is a different kind of number but still a long way from 8.

What does phase shifting actually cancel?

Phase shifting is the cheapest real harmonic fix for a group of drives, and it is almost never specified on a crane. The idea is simple: two 6-pulse rectifiers fed from windings that are 30 electrical degrees apart produce fifth and seventh harmonics that are 180 degrees apart, so they cancel at the shared busbar instead of adding. One 6-pulse plus one phase-shifted 6-pulse behaves like a 12-pulse rectifier at the point where they meet.

Published current distortion figures for the available front ends, from ABB and from Siemens harmonic data for drives at full load, explain why this matters.

Front end Typical current THDi at full load What it does to a five-drive busbar Realistic crane use
6-pulse, no reactor90 to 120 percentworst case dominatesvery common in low-cost control panels
6-pulse, 2 to 3 percent reactor43 to 44 percenthelps, still above 8common retrofit
6-pulse, 5 percent reactor34 to 45 percent15 to 18 percent if angles spreadstandard in HVAC, uncommon on cranes
12-pulse8.8 percentnear limit, needs a dual-winding transformerrare on cranes, common in steel plants
18-pulse3.9 percentbelow limitoccasionally, for large hoists
Active front end, two quadrant1.3 to 5 percentbelow limit, unity power factorincreasingly specified for high duty hoists
Active front end, four quadrant1.2 percent, plus regenerationbelow limit and recovers braking energypremium, justified above about 50 tonnes

One published demonstration is worth more than the table. Two identical 6-pulse drives on a shared bus, one phase-shifting transformer, fifth harmonic from 10.9 A per drive to roughly 21.8 A combined without shifting and to near zero with it. The transformer did not filter anything. It turned two in-phase waveforms into two opposite-phase waveforms.

On a double girder this is genuinely practical, because the two hoists are separate drives that do not have to be identical. A 20 tonne machine with a 16 kW main hoist and a 2.6 kW auxiliary can put the auxiliary on a phase-shifted feed, or simply on a separate small transformer with a different vector group. That cancels the fifth and seventh between the two largest sources for the price of a winding rather than an active front end.

What it does not do is cancel the four long-travel motors, which are identical, fed from one inverter pair in master/slave, and therefore perfectly in phase with each other. Identical drives fed from one inverter are not four harmonic sources. They are one source with four loads, which is why long travel is usually the least of the problems and the two hoists are usually the most.

Is a double girder always a VFD crane?

No, and this is the point where most buyers get the diagnosis backwards. The 50 tonne machine described earlier has 44.4 kW of electrical equipment and no inverter anywhere. Hoisting is two-speed pole change at 4 and 0.67 m/min. Long travel is two-speed pole change at 40 and 10 m/min. Trolley is 20 and 5 m/min. Every motion is contactor switched.

That machine does not produce significant harmonic current, because a pole-change induction motor is a linear load. It produces something else: a starting current of six to eight times full load current sustained until the motor reaches pull-up speed, with a first-cycle peak that can reach ten to twelve times according to ABB drive documentation. On a 44 kW machine that is a 500 to 800 A event at every start, and it happens a few hundred times an hour at M6 duty.

The two designs therefore need opposite mitigations.

Symptom Pole-change crane VFD crane The wrong answer
Lights flicker on each liftyes, starting currentless, unless the DC bus is at limitbuying a bigger transformer
Generator trips on startvery likelypossible if undersizedadding a harmonic filter
Neutral or earth current warmnoyes, triplen harmonicsreplacing the cable
Capacitor bank blows fusesunlikelyclassic harmonic resonancefitting a bigger capacitor
Contactor contact pittinghigh, from start currentlowerchanging contactor brand
Correct mitigationsoft starter or VFD retrofitreactor, then AFE or 12-pulseboth exist, they are not interchangeable

Our planning figures, based on the starting current ratios published by ABB and the motion speeds from the published 50 tonne data sheet. The takeaway is that the first question on any double girder power problem is not what the distortion is. It is whether there is an inverter at all. I have seen a harmonic filter quoted for a contactor-switched crane, which is a polite way of selling someone a transformer they do not need.

Why does the far end of a 200 metre runway behave differently?

Because the busbar is a resistor with an inductance, and the crane collects current at whichever point along it the bridge happens to be. A crane parked at the feed end sees almost no drop. The same crane at the far end sees the full conductor length, and on a long bay the numbers stop being academic.

Published impedance figures for shrouded conductor systems used on crane runways, at 35 degrees C, per metre.

Conductor Rating Impedance, ohm per metre DC resistance, ohm per metre
Aluminium, stainless steel contact face500 A0.0001580.000098
Aluminium800 A0.0001450.000075
Aluminium1000 A0.0001380.000052
Copper500 A0.0001620.000105
Copper800 A0.0001380.000058
Copper1000 A0.0001280.000035

The manufacturer's own worked examples on the same sheet are the useful part, because they show what happens when a bay is shared. Two cranes drawing 900 A total on a 1000 A aluminium busbar, 245 m bay length, end fed: 52.6 V of drop. The same bay in copper: 48.8 V. One crane drawing 1000 A on a 250 m 1000 A aluminium bar: 59.7 V. On a 400 V system that is 13.2 percent and 14.9 percent.

That is far outside any sensible limit, and it is not caused by the crane. It is caused by feeding a long bay from one end at close to the bar's rating. What the example really demonstrates is that a shared runway is an electrical design problem before it is a crane problem, and that the feed position matters more than the conductor material.

Where does the voltage drop budget actually go?

IEC 60364-5-52 Annex G is informative rather than mandatory, but it is the number everybody designs against: up to 3 percent for lighting circuits and up to 5 percent for other final circuits, measured from the point of supply. The same annex says explicitly that motor starting dip has to be checked separately, because meeting the steady-state limit does not guarantee a tolerable dip during a start.

So the question for a double girder is how much of that 5 percent the busbar eats. Our calculation below uses the published impedances above, end feed, 400 V, and the crane currents from the first table.

Crane Current Runway length Busbar Voltage drop Share of 400 V
20 t45.5 A150 m1000 A Al1.63 V0.41 percent
20 t45.5 A300 m1000 A Al3.26 V0.82 percent
50 t83.8 A200 m1000 A Al4.01 V1.00 percent
50 t83.8 A400 m1000 A Al8.01 V2.00 percent
100 t170 A300 m1000 A Al12.2 V3.05 percent
100 t170 A400 m500 A Al18.6 V4.65 percent
2 x 50 t together167.6 A400 m1000 A Al16.0 V4.01 percent
Published example, 2 cranes900 A245 m1000 A Al52.6 V13.2 percent

Our calculation from the published per-metre impedance, using the standard three-phase relation with conductor length equal to half the bay for a centre feed and the full bay for an end feed. All rows are end fed so the comparison is like for like.

The results are reassuring for the crane and uncomfortable for the runway. A single double girder at 45 to 84 A eats 0.4 to 2 percent of the budget, which is fine. Two of them sharing a 400 m bar eats 4 percent, which leaves almost nothing for the plant's own feeders. Three cranes at 900 A eats 13.2 percent, which is the published example and which is why a shared bay fails while each individual crane looks correct on paper.

One more thing the drop does that a meter will not show. It happens in the moving connection, at the collector shoes, not in a terminal box. Intermittent collector contact on a long bar is a classic source of what the industry calls weak motion at the far end: the contactor holds, the motor turns, and the load still will not lift. If your symptom appears only when the bridge is at one end of the bay, measure the voltage at the crane, not at the panel.

What do two hoist drives in one panel do to the enclosure?

They cook it. Inverter losses are published at 40 to 50 W per kVA of rating, or 3 to 5 percent of rated power. A 45 kW hoist drive at power factor 0.85 looks like about 53 kVA, so its full-load loss lands between 2.1 and 2.7 kW of heat inside a steel box.

A published worked example from a crane panel designer makes this concrete. A QDY type metallurgical main hoist panel accumulates about 1.68 kW of loss: 1.5 kW in the inverter, 0.07 kW in the busbar, 0.04 kW in contactors, 0.02 kW in the power supply and 0.05 kW of small items. The enclosure is 2,000 by 800 by 600 mm, installed free standing, which gives an effective heat transfer area of 5.712 square metres by the IEC TR 60890 relation. Painted steel transfers at about 5.5 W per square metre per kelvin. At 15 K rise the box sheds 471 W.

So 1.68 kW of loss in a box that naturally sheds 471 W settles at a rise of 1,680 divided by the product of 5.5 and 5.712, which is 53.5 K. In a 42 C workshop the inside of that panel runs at about 95 C.

Now add the second hoist. A double girder above 16 tonnes puts two inverter groups in the same enclosure, and the auxiliary is not negligible because the panel is shared.

Crane Installed drive power Heat at 3.5 percent Natural shedding at 15 K Settled rise, no fan Inside at 40 C ambient
10 t single girder14.1 kW0.49 kW471 W16 K56 C
20 t double girder24.1 kW0.84 kW471 W27 K67 C
32 t double girder33.2 kW1.16 kW471 W37 K77 C
50 t double girder44.4 kW1.55 kW471 W49 K89 C
50 t with one fan kit44.4 kW1.55 kW1,200 W with 250 m3/h of filtered airabout 15 Kabout 55 C

Our calculation, using the published loss rate, the published enclosure relation and the published derating curve. The last row uses a typical 250 cubic metre per hour filtered fan set and is indicative only; the fan supplier's curve governs.

Why it matters for distortion specifically. Published inverter derating is 1.5 percent of rated output current per degree above 40 C ambient. At 55 C inside the enclosure the drive has 77.5 percent of its rating left, so a 45 kW inverter behaves like a 35 kW inverter. A drive running at 78 percent of nameplate into a motor selected for the full load either trips on overcurrent or, worse, runs at a distorted operating point where the current waveform has more harmonic content than the datasheet figure it was specified against. Panel cooling is not a comfort item on a double girder. It is part of the harmonic compliance argument.

Two related habits from the same source are worth copying. Put the brake resistor outside the enclosure, because its surface reaches above 300 C during a regeneration cycle. And never mount a panel against a wall without redoing the heat calculation, because a wall mounted single enclosure loses about 11 percent of its effective area compared with a free-standing one.

Will the contactors ride through a dip?

Sometimes, and the margin is narrower than most buyers assume. A contactor's coil has a pick-up range and a release range, and the release range is wide. One published miniature contactor datasheet gives pick-up at 85 to 110 percent of rated coil voltage and release anywhere from 20 to 75 percent. If your particular unit releases at the top of that band, a 25 percent dip drops it out.

On a double girder that matters more than on a single girder because there are more contactors and more motions to lose. Losing one of four long-travel contactors leaves three motors driving one end and one motor coasting, which the master/slave control then tries to correct by pushing the other three harder. That is how a rail climbs.

Source Figure What it means on site
Published contactor datasheetpick-up 85 to 110 percent, release 20 to 75 percent of coil ratinga 25 percent dip can release a worst-case coil
IEC 60034-1, zone Aplus or minus 5 percent voltage, plus or minus 2 percent frequencymotor is safe, contactor may not be
IEC 60034-1, zone Bplus or minus 10 percent voltage, plus 3 to minus 5 percent frequencyrated torque available but hotter, short time only
NEMA MG 1plus or minus 10 percent voltage, plus or minus 5 percent frequency, combined not over 10the North American equivalent, slightly looser
EPRI ride-through studymost common sags last 5 to 15 cycles, 83 to 250 mslong enough for a coil to drop and re-close
Generator sizing practicemotors tolerate 30 to 35 percent, specifiers limit to 20 percentthe 20 percent is about contactors, not motors

The practical fix costs almost nothing and almost nobody does it: feed the control circuit from a small constant-voltage transformer or from a DC supply with a capacitor, so coil voltage does not track the power busbar. The other fix is to command motions sequentially rather than simultaneously, which the PLC can do for free.

What does 0.69 power factor cost on a double girder?

It depends entirely on whether the crane sets your monthly peak. Where it does, a published industrial tariff shows the damage. One rural electric cooperative rate sheet charges USD 11.56 per kW of purchased power demand plus USD 11.81 per kW of distribution demand, so about USD 23.37 per kW per month. The same sheet adjusts billing demand upward when the power factor at maximum demand is below 97 percent, multiplying recorded demand by 97 divided by the actual power factor. It also charges USD 0.01009 per excess kVARh when the monthly average falls below 95 percent.

A 6-pulse drive with no reactor has a true power factor near 0.69 even though the drive's displacement factor is 0.98, because the distortion term drags the total down. Here is what that does to a 24.1 kW crane.

Power factor Apparent demand Billed demand Penalty per month Penalty per year Likely cause
0.9824.6 kVA24.1 kWnonenoneactive front end
0.9325.9 kVA25.1 kWUSD 23USD 2815 percent reactor
0.8528.4 kVA27.5 kWUSD 79USD 9532 to 3 percent reactor
0.6934.9 kVA33.9 kWUSD 229USD 2,7486-pulse, no reactor
0.69, two cranes peaking together69.8 kVA67.8 kWUSD 458USD 5,496same, doubled

Our calculation applied to the published tariff and the crane's 24.1 kW, at USD 23.37 per kW per month. Two honest caveats. This only bites where the crane is coincident with the billing peak, which is typical in a foundry or a precast yard and atypical in a warehouse where the crane runs occasionally. And it assumes the utility applies the letter of that particular tariff, which varies by region.

Where it does bite, a reactor costing a few hundred dollars returns four figures a year. That is the entire commercial case for specifying reactors on a double girder, and it has nothing to do with being a good citizen.

Four long-travel motors and one master: what goes wrong?

Heavy overhead cranes run up to four travel motors synchronously, with synchronisation provided by one crane inverter in master/slave mode. Published drive data for crane duty puts travel motors at 1.8 times rated torque for starting, S4 duty at 40 percent cyclic duration factor, up to 360 starts per hour, and NEMA MG 1 Part 31 insulation for inverter compatibility.

Two electrical failure modes belong to this arrangement and to nothing else on the crane. The first is torque skew: if one slave lags, the master increases torque on all four, the leading end carriage slips or climbs the rail, and the crane skews in the runway. The second is circulating current between motors connected to the same DC bus when their cable lengths differ significantly, which shows up as unequal heating in the motors that a thermal camera finds long before a fault code does.

Neither is a harmonic problem, and both are frequently blamed on harmonics because the symptom is a trip. If your trips happen during long travel and never during hoisting, you are looking at a drive coordination problem, not a power quality problem.

Does duty class decide whether any of this matters?

Almost entirely. Published design limits for hoists, cross referenced across ISO, FEM, CMAA and AS classifications, put a hard ceiling on running hours and starts per hour for each class.

Class ISO / AS FEM CMAA Running hours per day Starts per hour
4M41AmB2180
5M52mC4240
6M63mD8300
7M74mE16360
8M85mF16 plus360

A machine at M5 accumulates roughly 8 million starts over its life at four hours a day. A machine at M7 accumulates about four times that, because the class ceiling is four times higher. The harmonics per start do not change. The number of starts in which harmonics and starting current coincide with everything else on the plant does.

Which standard actually applies to your crane?

This is where a 5 to 100 tonne range splits, and it splits in an awkward place. Harmonic emission limits for equipment connected to public low-voltage systems at 16 to 75 A per phase are set by IEC 61000-3-12. A 20 tonne double girder at 45.5 A sits inside that window. A 50 tonne at 83.8 A sits outside it, and the same product family is then judged against the utility's own distortion limit rather than the equipment standard.

Document Scope Where a double girder lands
IEC 61000-3-2input current up to 16 A per phaseonly the smallest machines, 5 t at 16.6 A is already outside
IEC 61000-3-1216 to 75 A per phase, up to 690 V, 50 or 60 Hz, public low voltage5 to 32 t fall inside; 40 t and 50 t fall outside
IEEE 519-2022current and voltage distortion at the point of common coupling, limits scaled by short-circuit ratiothe applicable limit in most export contracts, TDD 5 to 20 percent depending on ratio
IEC 60204-32:2023electrical equipment of hoisting machines from the crane supply switch onward, including conductor bars and festoon outside the machine, up to 1000 V ACcovers the runway supply, which is the part most often left out of the crane contract
IEC 60364-5-52 Annex Grecommended voltage drop, 3 percent lighting, 5 percent other final circuits, starting dip checked separatelythe budget the runway eats into
IEC 61800-5-1electrical safety of power drive systems, including earth leakage protectiondrives can produce smooth DC residual current, so a Type B or B+ device is required

The IEEE 519-2022 voltage table is worth carrying around, because it is the one buyers quote without the qualifier. At the point of common coupling below 1 kV the limit is 5.0 percent for any single harmonic and 8.0 percent total. From 1 to 69 kV it tightens to 3.0 and 5.0. The current table that everybody forgets scales with the short-circuit ratio: 4.0 percent for the fifth harmonic and 5.0 percent TDD when the ratio is below 20, rising to 15.0 and 20.0 when it is above 1,000. A crane in a plant with a stiff supply has more headroom than the same crane at the end of a long rural feeder, and the equipment is identical.

On earth leakage, the crane-specific point is that a Type AC or Type A device can be blinded by the smooth DC component a drive produces under a fault. Published device literature for crane installations recommends Type B or Type B+ with immunisation against nuisance tripping on long cables, and notes that an integrated EMC filter is only declared effective within about 5 to 10 m of shielded motor cable. On a double girder with a panel at one end and a hoist at the other, that distance is routinely exceeded, which is exactly the situation the immunised devices exist for.

What should go in the RFQ?

Ten lines, all of them answerable on one page by any competent supplier. I would rather have these than a compliance certificate with no numbers behind it.

1. Number of separately switched motors and, for each, whether the front end is 6-pulse, 12-pulse or active. 2. Reactor or filter fitted, percentage impedance, AC side or DC link. 3. Busbar material, current rating, number and position of feed points, and the calculated drop at the crane's current over the actual bay length. 4. How many cranes share the bar and what simultaneity the design assumes. 5. Panel heat load in kW, cooling method, and the ambient temperature at the panel location in summer. 6. Coil voltage and hold-in tolerance, and whether the control circuit has its own transformer. 7. Motor insulation to NEMA MG 1 Part 31 if inverters are fitted. 8. Earth leakage device type and setting, and whether it is immune to multifrequency residual current. 9. Duty class to ISO 4301, FEM or CMAA, with starts per hour. 10. Which harmonic limit the supplier is designing to, and at which point of measurement.

If you get a quotation that says only that the crane is CE marked, none of those ten have been answered. That is not a criticism of CE marking. It is an observation that CE marking says nothing about the tenth crane in your bay.

For machines already running, the order of work below is what I would actually do, sorted by return rather than by elegance.

Action Cost What it fixes Payback
Move the panel out of the hot zone and add a fan kitUSD 400 to 1,50020 to 25 K of internal rise, restores full drive ratingunder 1 year where trips are frequent
Feed the control circuit from a constant-voltage sourceUSD 200 to 600contactor dropout on dipsimmediate
5 percent reactor on every drive with noneUSD 200 to 600 per driveTHDi from about 100 to about 40 percent, power factor from 0.69 to 0.936 to 18 months on demand charges
Second feed point at the mid-span of the runwayUSD 1,500 to 5,000halves the drop on a long baythe only real cure for weak motion at the far end
Phase-shifted feed for the auxiliary hoistUSD 2,000 to 6,000cancels 5th and 7th between the two largest drives2 to 6 years depending on the limit
Active front end on the main hoistUSD 3,000 to 9,000 premiumTHDi under 5 percent, unity power factor, regeneration3 to 8 years, faster on high duty
Harmonic filter on the plant busbar instead of the craneUSD 4,000 to 12,000the shared problem, if several cranes contributedepends entirely on what else is on the bus
Fitting a harmonic filter to a contactor-switched craneUSD 3,000 to 8,000nothing, because there are no rectifiersnever. Fit a soft starter instead

Costs are our planning figures for 2026, European and Middle East supply. The last row is in the table on purpose. It is the mistake I see most often, and it is the one that gets signed off because the word filter sounds like engineering.

Frequently Asked Questions

Do harmonics from a double girder get worse with two hoists?

Yes, but not for the reason people assume. The two hoist drives add their harmonic currents at the busbar before the current reaches your transformer, and similar drives with similar phase angles add close to arithmetically. A published laboratory demonstration measured the fifth harmonic from one drive at 10.9 A and roughly double that with a second drive running. The auxiliary is the more awkward of the two because it is small and runs at a poor operating point. Our double girder crane range lists both hoists separately for exactly this reason.

Is a 5 percent reactor enough on a five-drive machine?

No, and this is the part that surprises buyers. A reactor takes an individual drive from about 100 percent current THDi to about 40 percent, which is a large improvement and worth the money. On a five-drive busbar the resulting total demand distortion still lands around 15 to 18 percent even if the phase angles distribute perfectly, against an IEEE 519 limit of 8 percent. The reactor is necessary and not sufficient. Phase shifting or an active front end is what closes the rest of the gap.

Why does my crane only misbehave at one end of the runway?

Because the busbar is the circuit, and the crane collects current at whichever point it has reached. A published conductor sheet gives 0.000138 ohm per metre for a 1000 A aluminium bar, which puts a 245 m bay shared by cranes drawing 900 A at 52.6 V of drop, or 13.2 percent of 400 V. A single double girder at 45 to 84 A eats only 0.4 to 2 percent, so the symptom you are seeing is almost always a shared bay. Add a mid-span feed point before you replace anything.

Can a double girder have no inverter at all?

Yes, and many do. A published 50 tonne, 13.5 m double girder lists 44.4 kW of electrical equipment with two-speed pole-change motors on hoist, trolley and long travel, and no drive anywhere. That machine produces almost no harmonic current, because a pole-change induction motor is a linear load. It produces a starting current six to eight times full load instead, and the correct mitigation is a soft starter, not a filter. Ask which design you are buying before you accept a harmonic solution.

Why does the electrical panel overheat on a double girder?

Because two inverter groups share one enclosure and inverter losses run at 3 to 5 percent of rated power. A published worked example puts a single 45 kW hoist panel at 1.68 kW of internal loss in a box that sheds 471 W naturally at 15 K rise, which settles at a 53.5 K rise and about 95 C inside at a 42 C workshop. Inverters derate 1.5 percent of output current per degree above 40 C, so a 45 kW drive behaves like a 35 kW drive. Fit the fan kit and put the brake resistor outside the cabinet.

What is the cheapest change that pays for itself?

Panel cooling, then control-circuit voltage, then reactors, in that order. The fourth item that pays is a second feed point on the runway, but only if the symptom is weak motion at the far end rather than distortion. If your plant applies a power factor adjustment, a few hundred dollars of reactor on a 24.1 kW crane saves around USD 2,700 a year at a true power factor of 0.69, based on a published tariff charging about USD 23.37 per kW of demand.

Related Articles

Related articles:
Crane Power Quality: What a Single Girder Crane Does to a Weak Grid
Double Girder Crane Energy Consumption: What a 5 to 100 Tonne Machine Really Costs to Run
Double Girder Crane Installation: Assembling the Bridge on Site
Crane Embodied Carbon: What a 20 Tonne Double Girder Actually Carries
Hoist Energy Consumption: Where the Kilowatt Hours Actually Go